SNMP LLD with Multiple OID, Filters if one has no value
If I have a multiple item LLD discovery, e,g.
discovery[{#VAL1},SOMEMIB:OID1, {#VAL2},OTHERMIB:OID2]
I want to write a filter condition that says "use this discovery only if {#VAL2} is not returned."
I've tried matching {#VAL2} to blank, ^$, and various other things without success as the match pattern in the filter without luck. The documentation says
Can this be done?
The manual says:
But I do not know what "the found entity" means in this regard, unless it means the filter condition is always false? The behavior is indeed that it does not discover, and I want exactly the opposite behavior (including that it not discover when the value is found).
discovery[{#VAL1},SOMEMIB:OID1, {#VAL2},OTHERMIB:OID2]
I want to write a filter condition that says "use this discovery only if {#VAL2} is not returned."
I've tried matching {#VAL2} to blank, ^$, and various other things without success as the match pattern in the filter without luck. The documentation says
Can this be done?
The manual says:
Code:
Note that if some macro from the filter is missing in the response, the found entity will be ignored.