Hi Guys,
I am new to this forum and have a question rather a problem I am encountering while accessing Zabbix API from my Linux Machine. The error is as follows: I am getting a 403 forbidden error, this happens only when I access from Linux, if I install Python on windows and make the same API call it works just fine.
Type "help", "copyright", "credits" or "license" for more information.
>>> from pyzabbix import ZabbixAPI
>>> zapi = ZabbixAPI("http://myserverzabbix")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 156, in __init__
self._login(user, password)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 186, in _login
self.auth = self.user.login(user=user, password=password)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 82, in fn
args or kwargs
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 236, in do_request
res = urlopen(req)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 109, in inner
res = func(req)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 118, in urlopen
return urllib2.urlopen(*args, **kwargs)
File "/usr/lib64/python2.7/urllib2.py", line 154, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib64/python2.7/urllib2.py", line 437, in open
response = meth(req, response)
File "/usr/lib64/python2.7/urllib2.py", line 550, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib64/python2.7/urllib2.py", line 475, in error
return self._call_chain(*args)
File "/usr/lib64/python2.7/urllib2.py", line 409, in _call_chain
result = func(*args)
File "/usr/lib64/python2.7/urllib2.py", line 558, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
>>>
I am new to this forum and have a question rather a problem I am encountering while accessing Zabbix API from my Linux Machine. The error is as follows: I am getting a 403 forbidden error, this happens only when I access from Linux, if I install Python on windows and make the same API call it works just fine.
Type "help", "copyright", "credits" or "license" for more information.
>>> from pyzabbix import ZabbixAPI
>>> zapi = ZabbixAPI("http://myserverzabbix")
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 156, in __init__
self._login(user, password)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 186, in _login
self.auth = self.user.login(user=user, password=password)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 82, in fn
args or kwargs
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 236, in do_request
res = urlopen(req)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 109, in inner
res = func(req)
File "/usr/lib/python2.7/site-packages/pyzabbix/api.py", line 118, in urlopen
return urllib2.urlopen(*args, **kwargs)
File "/usr/lib64/python2.7/urllib2.py", line 154, in urlopen
return opener.open(url, data, timeout)
File "/usr/lib64/python2.7/urllib2.py", line 437, in open
response = meth(req, response)
File "/usr/lib64/python2.7/urllib2.py", line 550, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib64/python2.7/urllib2.py", line 475, in error
return self._call_chain(*args)
File "/usr/lib64/python2.7/urllib2.py", line 409, in _call_chain
result = func(*args)
File "/usr/lib64/python2.7/urllib2.py", line 558, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
>>>
Comment